Rats! I didn't catch that.markrob wrote: That response is looking really nice. You seem to have a good handle on things. One odd thing. I think you might have the polarity flipped. The phase display starts out at -90 degrees at low frequencies and transitions to +90 after resonance. It should be just the opposite (+90 at low frequencies and -90 after system resonance.
What is the distance from the drive coil to the phono pickup? The extra phase lag could be due, in part, to the sound propagation delay from the driver to the pickup. It could also be due to the driver L/R time constant. One way around that (if it is the source of the lag) is to drive the head using a constant current source rather than a constant voltage. That can be done easily with a second feedback loop around the power amp with a small current sense resistor in the ground return of the head.
In any event, it looks like you should be able to close the loop beyond 8 Khz with a bit of lead lag compensation.
I'll check again since I took it apart to remove that epoxy. I used super glue this time.
I'll also look at it with and without the rod support on the test jig.
The total rod length is 67mm, and the notch for the stylus is 44mm from the driver.
We had talked about the L/R time constant at one point, and adding a resistor in series (since I have power to burn). Right now I have a 10 ohm in series with the driver. But I also have a 2uF in parallel with the 10 ohm. That 10 ohm / 2uF gives me about a 3db boost at 10K, and about a 6db boost at 20K. But it also gives me a +30 degree phase shift from about 10Khz-20Khz. Down around 2.5Khz (where the new resonance is) it's about 12 degrees, but again in a positive direction. So it still seams beneficial. What do you think?
As far as the second feedback loop, and current sensing are we talking about doing something like this?
http://www.current-drive.info/9
I've used shunt resisters before to make current measurements but I'm note sure what would be involved in this application. Do you have time to sketch up something?
Also, earlier when I said 0.76 watts is 1.42cm/s at the driver rod, I forgot this represents only 1/2 the velocity on an actual groove because one driver only is cutting 1/2 of the mono sine wave. So if both drivers are running (out of phase) shouldn't the velocity of the groove actually be twice that? That sounds more reasonable, right?
Bryan